document.write( "Question 386107: Find the eccentricity of the ellipse given by: x^2/144 + y^2/63 = 1 \n" ); document.write( "
Algebra.Com's Answer #278096 by lwsshak3(11628)\"\" \"About 
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given: x^2/144 + y^2/63 = 1
\n" ); document.write( "Standard form of ellipse: x^2/a^2 + y^2/b^2 =1, a>b\r
\n" ); document.write( "\n" ); document.write( "a^2=144
\n" ); document.write( "a=12
\n" ); document.write( "b^2=63
\n" ); document.write( "b=sqrt(63)
\n" ); document.write( "c^2=a^2-b^2
\n" ); document.write( "c=sqrt(a^2-b^2)=sqrt(144-63)=sqrt(81)=9
\n" ); document.write( "eccentricity = c/a=9/12=.75\r
\n" ); document.write( "\n" ); document.write( "ans: eccentricity of given ellipse = .75
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