document.write( "Question 390664: hi. if my hypotenuse is 600, and the perimeter of the entire triangle is 1400, how long is the two other sides?
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Algebra.Com's Answer #278089 by robertb(5830)\"\" \"About 
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From the Pythagorean theorem, \"x%5E2+%2B+y%5E2+=+360000\".
\n" ); document.write( "From the perimeter condition, x + y + 600 = 1400, or y = 800 - x.
\n" ); document.write( "Substitute this into the 1st equation, to get
\n" ); document.write( "\"x%5E2+%2B+%28800+-+x%29%5E2+=+360000\",
\n" ); document.write( "<==> \"2x%5E2+-+1600x+%2B+280000+=+0\",
\n" ); document.write( "<==> \"x%5E2+-+800x+%2B+140000+=+0\".
\n" ); document.write( "Using the quadratic formula, we get\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28800+%2B-+200sqrt%282%29%29%2F2+=+400+%2B-+100sqrt%282%29+\".
\n" ); document.write( "If \"x+=+400+%2B+100sqrt%282%29\", then \"y+=+400+-+100sqrt%282%29\".
\n" ); document.write( "If \"x+=+400+-+100sqrt%282%29\", then \"y+=+400+%2B+100sqrt%282%29\".
\n" ); document.write( "Hence there is only 1 pair of values for the legs, and those are \"+400+-+100sqrt%282%29\" and \"400+%2B+100sqrt%282%29\".
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