document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=391888>Question 391888</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone please help with this Algebra problem? I am so confused by this.\r<BR>\n" );
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document.write( "Use an associative law to find an expression equivalent to s+(r + 36) \r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #278043 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=278043\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use an associative law to find an expression equivalent to s+(r + 36) <BR>\n" );
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document.write( "Ans: (s+r)+36<BR>\n" );
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document.write( "Associate means to group.  You can group added terms<BR>\n" );
document.write( "in various ways and they will all have the same value.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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