document.write( "Question 391849: A chemist has one solution that is 30% pure salt and another is 60% pure salt. how many ounces of each solution must he use to produce 60 ounces of a solution that is 50 % salt. \n" ); document.write( "
Algebra.Com's Answer #278019 by josmiceli(19441)\"\" \"About 
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In words:
\n" ); document.write( "(salt in final solution)/(salt + water in final solution) = 50%
\n" ); document.write( "Let \"a\" = ounces of 30% solution needed
\n" ); document.write( "Let \"b\" = ounces of 60% solution needed
\n" ); document.write( "given:
\n" ); document.write( "(1) \"a+%2B+b+=+60\"
\n" ); document.write( "\".3a\" = ounces of salt in 30% solution
\n" ); document.write( "\".6b\" = ounces of salt in 60% solution
\n" ); document.write( "(2) \"%28.3a+%2B+.6b%29%2F%28a+%2B+b%29+=+.5\"
\n" ); document.write( "\".3a+%2B+.6b+=+.5a+%2B+.5b\"
\n" ); document.write( "\".2a+=+.1b\"
\n" ); document.write( "\"2a+=+b\"
\n" ); document.write( "Substitute this in (1)
\n" ); document.write( "\"a+%2B+2a+=+60\"
\n" ); document.write( "\"3a+=+60\"
\n" ); document.write( "\"a+=+20\"
\n" ); document.write( "and , from (1)
\n" ); document.write( "\"20+%2B+b+=+60\"
\n" ); document.write( "\"b+=+40\"
\n" ); document.write( " 20 ounces of 30% solution are needed
\n" ); document.write( " 40 ounces of 60% solution are needed
\n" ); document.write( "check answer:
\n" ); document.write( "(2) \"%28.3a+%2B+.6b%29%2F%28a+%2B+b%29+=+.5\"
\n" ); document.write( "(2) \"%28.3%2A20+%2B+.6%2A40%29%2F%2820+%2B+40%29+=+.5\"
\n" ); document.write( "\"%286+%2B+24%29%2F60+=+.5\"
\n" ); document.write( "\"30+=+.5%2A60\"
\n" ); document.write( "\"30+=+30\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );