document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=391849>Question 391849</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has one solution that is 30% pure salt and another is 60% pure salt. how many ounces of each solution must he use to produce 60 ounces of a solution that is 50 % salt. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #278017 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=278017\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist has one solution that is 30% pure salt and another is 60% pure salt. how many ounces of each solution must he use to produce 60 ounces of a solution that is 50 % salt. \r<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "salt + salt = salt<BR>\n" );
document.write( "0.30x + 0.60(60-x) = 0.50*60<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "30x + 60*60-60x = 50*60<BR>\n" );
document.write( "-30x = -10*60<BR>\n" );
document.write( "x = 20 oz (amt. of 30% solution needed in the mix)<BR>\n" );
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document.write( "60-x = 40 oz (amt. of 60% solution needed in the mix)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "stan H.  </SPAN>\n" );
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