document.write( "Question 391608: A corner lot that originally was square lost 185 m squared of area when one of the adjacent streets was widened by 3m and the other was widened by 5 m. Find the new dimensions of the lot. HINT let x = the length of a side of the original square lot. \n" ); document.write( "
Algebra.Com's Answer #278002 by ankor@dixie-net.com(22740)\"\" \"About 
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A corner lot that originally was square lost 185 m squared of area when one of the adjacent streets was widened by 3m and the other was widened by 5 m. Find the new dimensions of the lot. HINT let x = the length of a side of the original square lot.
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\n" ); document.write( "Let one of the new dimensions = (x-3)
\n" ); document.write( "Let the other new dimension = (x-5)
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\n" ); document.write( "The original area = x^2
\n" ); document.write( "the new area = (x^2-185)
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\n" ); document.write( "we have the new area equation
\n" ); document.write( "(x-3)*(x-5) = x^2 - 185
\n" ); document.write( "FOIL the left side
\n" ); document.write( "x^2 - 5x - 3x + 15 = x^2 - 185
\n" ); document.write( "combine like terms
\n" ); document.write( "x^2 - x^2 - 8x = -185 - 15
\n" ); document.write( "-8x = -200
\n" ); document.write( "x = \"%28-200%29%2F%28-8%29\"
\n" ); document.write( "x = +25 the original length of the side of the square
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\n" ); document.write( "The new dimensions
\n" ); document.write( "25 - 3 = 22m is the new width
\n" ); document.write( "25 - 5 = 20m is the new length
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\n" ); document.write( "see if this is true by finding the difference in area
\n" ); document.write( "25^2 - (22*20) =
\n" ); document.write( "625 - 440 = 185, confirms our solutions \n" ); document.write( "
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