document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=391804>Question 391804</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm having a problem with following equation using Substitution algebra.  I understand substitution however this particular equation has me stumped.\r<BR>\n" );
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document.write( " 4y + x = -2   <BR>\n" );
document.write( " x = -4y \r<BR>\n" );
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document.write( "I understand I need to plug the -4y in for the x in the first equation.  What I don't understand is how to get the 4y on the other side of = sign in order to isolate the y.\r<BR>\n" );
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document.write( "Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #277966 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=277966\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4y + x = -2 <BR>\n" );
document.write( "x = -4y <BR>\n" );
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document.write( "If you sub for x:<BR>\n" );
document.write( "4y + (-4y) = -2<BR>\n" );
document.write( "0 = -2<BR>\n" );
document.write( "There's no solution.<BR>\n" );
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document.write( "4y + x = -2 --> x = -4y - 2<BR>\n" );
document.write( "x = -4y <BR>\n" );
document.write( "If you graph these, you get 2 parallel lines.  No intersection, no solution.<BR>\n" );
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