document.write( "Question 391758: Suppose the variable X has a normal distribution with mean 36 inches and standard deviation 2 inches.What X value approximates the 84th percentile of this distribution, that is what X value will have approximately 84% of the distribution to its left? \n" ); document.write( "
Algebra.Com's Answer #277936 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "variable X with a normal distribution with mean 36 inches and standard deviation 2 inches
\n" ); document.write( "finding the X value approximating the 84th percentile of this distribution
\n" ); document.write( "*Note: \"z+=+blue%28x+-+mu%29%2Fblue%28sigma%29\"
\n" ); document.write( " (X - 36)/2 = .9945 |Using Excel function: NORMSINV(0.84)
\n" ); document.write( " X = 2*.9945 +36
\n" ); document.write( " X = 37.989 or 38 will approxiamate the 84th percentile \n" ); document.write( "
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