document.write( "Question 391728: find the vertex of the parabola,x2+4x+2y-7=0. \n" ); document.write( "

Algebra.Com's Answer #277910 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "the vertex form of a parabola,  where(h,k) is the vertex
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document.write( "x2+4x+2y-7=0   OR y = (1/2)x^2 - 2x - 7/2
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document.write( "  2y = -x^2 - 4x - 7
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document.write( "   y = -(1/2)x^2 - 2x - 7/2
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document.write( "Completing the square to put into vertex form
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document.write( " y = -(1/2)[x^2+4x] - 7/2
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document.write( " y = -(1/2)[(x+2)^2 - 4] -7/2
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document.write( " y = -(1/2)(x+2)^2   +2 -7/2
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document.write( " y = -(1/2)(x+2)^2 - 3/2
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document.write( "Vertex is Pt(-2,-3/2)  This is a maximum point, parabola opens downward -(1/2) < 0
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