document.write( "Question 391701: Find three consecutive integers such that the product of the first and the third is 440. \n" ); document.write( "
Algebra.Com's Answer #277892 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi,
\n" ); document.write( "Let x,(x+1),(x+2) represent the three consecutive integers
\n" ); document.write( "question states****
\n" ); document.write( " x(x+2) = 440
\n" ); document.write( "x^2 + 2x - 440 = 0
\n" ); document.write( "factoring
\n" ); document.write( "(x+22)(x-20)= 0 Note:SUM of the inner product(22x) and the outer product(-20x) = 2x
\n" ); document.write( "(x+22)= 0
\n" ); document.write( " x = -22 three consecutive integers -22,-21,-20
\n" ); document.write( "or
\n" ); document.write( "(x-20)= 0
\n" ); document.write( " x = 20 three consecutive integers 20,21,22\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer
\n" ); document.write( "-22*-30 = 440
\n" ); document.write( "10*22 = 440 \n" ); document.write( "
\n" );