document.write( "Question 391551: I'm trying to help my niece with her homework and I can't remember at all how to solve this problem.\r
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document.write( "She's trying to solve this linear equation or system. She says she's supposed to get the answer by using the 3y?\r
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document.write( "2x-3y=-7 (negative 7)
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document.write( "3x+y=-5 (negative 5)\r
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document.write( "I have the answer for her but would really like to know how to solve this and to show her the correct way. \r
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document.write( "Thank you! \n" );
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Algebra.Com's Answer #277890 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 2x - 3y = -7 \n" ); document.write( "3x + y = -5 \n" ); document.write( "They probably want you to use elimination, by multiplying the 2nd equation by \n" ); document.write( "3 and adding the two equations, you will eliminate y and easily can find x \n" ); document.write( ": \n" ); document.write( "2x - 3y = -7 \n" ); document.write( "9x + 3y = -15 (multiplied by 3) \n" ); document.write( "---------------- \n" ); document.write( "11x + 0 = -22 \n" ); document.write( "Divide both sides by 11, and you have \n" ); document.write( "x = -2 \n" ); document.write( ": \n" ); document.write( "You can now find y by substituting -2 for x in the 2nd equation \n" ); document.write( "3(-2) + y = -5 \n" ); document.write( "-6 + y = -5 \n" ); document.write( "Add 6 to both sides \n" ); document.write( "y = -5 + 6 \n" ); document.write( "y = +1 \n" ); document.write( ": \n" ); document.write( "Check your solutions by substitution in the 1st equation \n" ); document.write( "2x - 3y = -7 \n" ); document.write( "2(-2) - 3(1) = -7 \n" ); document.write( "-4 - 3 = -7; confirms our solutions of x = -2, y = 1 \n" ); document.write( " |