document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=391694>Question 391694</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help on the following word problem: A ring is made out of gold and copper.  Gold has a density of 19.3 g/cm3.  Copper has a density of 9 g/cm3.  Mass m, density d, and volume v are related by the formula m=dv.  The ring has a volume of 8.4 cm3, and a mass of 104.44g.<BR>\n" );
document.write( "Let a=volume of gold, let c=volume of copper, mass of gold =dv=19.3a, mass of copper=dv=9c.  \r<BR>\n" );
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document.write( "Solve the following system by elimination to find out how many grams of gold are in the ring.<BR>\n" );
document.write( "a+c = 8.4<BR>\n" );
document.write( "19.3a+9c=104.44\r<BR>\n" );
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document.write( "also what is the percent of gold by mass? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #277888 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=277888\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I need help on the following word problem: A ring is made out of gold and copper.  Gold has a density of 19.3 g/cm3.  Copper has a density of 9 g/cm3.  Mass m, density d, and volume v are related by the formula m=dv.  The ring has a volume of 8.4 cm3, and a mass of 104.44g.<BR>\n" );
document.write( "Let a=volume of gold, let c=volume of copper, mass of gold =dv=19.3a, mass of copper=dv=9c.  \r<BR>\n" );
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document.write( "Solve the following system by elimination to find out how many grams of gold are in the ring.<BR>\n" );
document.write( "a+c = 8.4..............................1<BR>\n" );
document.write( "19.3a+9c=104.44........................2<BR>\n" );
document.write( "multiply (1)by -9<BR>\n" );
document.write( "-9a-9c=-75.6<BR>\n" );
document.write( "add this to (2)<BR>\n" );
document.write( "19.3a-9a+9c-9c=104.44-75.6<BR>\n" );
document.write( "10.3a=28.84<BR>\n" );
document.write( "/10.3a<BR>\n" );
document.write( "a=28.84/10.3<BR>\n" );
document.write( "a= 2.8 cm^3 = volume of gold<BR>\n" );
document.write( "a+c=8.4<BR>\n" );
document.write( "plug value of a<BR>\n" );
document.write( "2.8+c=8.4<BR>\n" );
document.write( "c=8.4-2.8<BR>\n" );
document.write( "c=5.6 cm^3 volume of copper<BR>\n" );
document.write( "...<BR>\n" );
document.write( "mass of copper = 5.6*9= 50.4 gm<BR>\n" );
document.write( "....\r<BR>\n" );
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document.write( "d gold = 19.3 gm/cm^3<BR>\n" );
document.write( "m=19.3*2.8<BR>\n" );
document.write( "mass of gold = 54.04 gm.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Total mass of ring = 54.04+50.40=104.44 gm<BR>\n" );
document.write( "...<BR>\n" );
document.write( "gold % = (54.04/104.44)*100<BR>\n" );
document.write( "gold % = 51.74\r<BR>\n" );
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document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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