document.write( "Question 391536: a rectangle has a length that is twice its width. the perimeter of the rectangle is 420. find the length of the diagonal of the rectangle \n" ); document.write( "
Algebra.Com's Answer #277776 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "
\n" ); document.write( "Hi,
\n" ); document.write( "Let x AND 2x represent the width and length respecively
\n" ); document.write( "Question states;
\n" ); document.write( " 2(2x) + 2x = 420
\n" ); document.write( " 4x + 2x = 420
\n" ); document.write( " 6x = 420
\n" ); document.write( " x = 70, the width. Length is 140 (2*70)
\n" ); document.write( "Applying the Pythagorean theorem
\n" ); document.write( " 70^2 + 140^2 = d^2
\n" ); document.write( " 156.5248 is the length of the diagonal \n" ); document.write( "
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