document.write( "Question 391504: Hi, Here is the question. The base of a triangle is 4 cm greater than the height. The area is 30cm^2, find the height and length.
\n" ); document.write( " I have done this so far,A=1/2 bh=30
\n" ); document.write( "bh=60
\n" ); document.write( "(h+4)H=60
\n" ); document.write( "H^2+4h=60
\n" ); document.write( "h^2 +4h - 60 =0
\n" ); document.write( "(h+ ) *(h- ) This is where I get very confused. I know triangles must add up to 90 , any help would be greatly appreciated! \n" ); document.write( "
Algebra.Com's Answer #277763 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Hi, Here is the question. The base of a triangle is 4 cm greater than the height. The area is 30cm^2, find the height and length.
\n" ); document.write( "I have done this so far,
\n" ); document.write( "A= (1/2)bh = 30
\n" ); document.write( "---
\n" ); document.write( "(1/2)(x+4)x = 30
\n" ); document.write( "x^2+4x = 60
\n" ); document.write( "x^2+4x-60 = 0
\n" ); document.write( "x^2+10x-6x-60 = 0
\n" ); document.write( "x(x+10)-6(x+10) = 0
\n" ); document.write( "(x+10)(x-6) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 6cm(height)
\n" ); document.write( "x+4= 10cm(base)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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