document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=391478>Question 391478</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary. One is 56 degrees more than 3 times the other. Find the measures of the angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #277758 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=277758\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary. One is 56 degrees more than 3 times the other. Find the measures of the angles<BR>\n" );
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document.write( "Angle: x<BR>\n" );
document.write( "Supplementary Angle: 180-x<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x = 3(180-x)+56<BR>\n" );
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document.write( "x = 3*180-3x+56<BR>\n" );
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document.write( "4x = 596<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x = 149<BR>\n" );
document.write( "180-x = 31<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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