document.write( "Question 391379: 10 years ago the father was 7times older than his son.2 years hence 2 times the fathers age will be 5 times the sons age.what are there present age. \n" ); document.write( "

Algebra.Com's Answer #277689 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,         
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document.write( "Let x and 7x represent the son's and father's ages 10 year ago.
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document.write( "Question states***
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document.write( "2(7x+12) = 5(x + 12)
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document.write( "solving for x
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document.write( " 14x + 24 = 5x = 60
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document.write( "      9x = 36
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document.write( "       x = 4, son's age 10 years ago. His father 28, ten year ago
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document.write( " Son is NOW 14 and his father 38\r
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document.write( "CHECKING our Answer using status 2 years from NOW
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document.write( " 2*(38+2) = 5*(14+2) = 80 \n" );
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