document.write( "Question 391386: How many different 5 digit codes are possible using the keypad show ,if the frist digit cannot be 0 and no digit may be use more than one? \n" ); document.write( "
Algebra.Com's Answer #277681 by MathLover1(20850)\"\" \"About 
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\"five\" digit codes using \"10\" digits, first one can't be \"0\"\r
\n" ); document.write( "\n" ); document.write( "think of choices per digit - they \"can%27t\" repeat, so one digit is used each time\r
\n" ); document.write( "\n" ); document.write( "\"9+%2A+9+%2A+8+%2A+7+%2A+6=27216\"\r
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\n" ); document.write( "\n" ); document.write( "Well, basically all you do in this problem is multiply.
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\n" ); document.write( "- put down \"5\" blank spaces on paper and then put the number of combinations in each space. \r
\n" ); document.write( "\n" ); document.write( "For example, there are \"10\" total digits that can be used (0-9). \r
\n" ); document.write( "\n" ); document.write( "However the \"first\" digit can not be \"0\", so there are \"9\" possible combinations (1-9). \r
\n" ); document.write( "\n" ); document.write( "The \"second\" digit cannot be the same as the first digit, but it can be \"0\", so there are \"9\" combinations. \r
\n" ); document.write( "\n" ); document.write( "The \"third\" digit cannot be either the first or the second digit and thus there are \"8\" combinations. \r
\n" ); document.write( "\n" ); document.write( "The \"fourth\" digit has \"7\" combinations and the fifth has \"6+\"combinations. so if you multiply the\r
\n" ); document.write( "\n" ); document.write( " numbers of combinations you should have \r
\n" ); document.write( "\n" ); document.write( "\"9+x+9+x+8+x+7+x+6+=+27216\"\r
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