document.write( "Question 391126: a rectangle is 6 cm long and 4 cm wide. If each dimension is increased by the same number of centimeters, a new rectangle is formed whose area is 39 square centimeters more than the area of the original rectangle. By how may centimeters was each dimension increased? \n" ); document.write( "
Algebra.Com's Answer #277621 by lwsshak3(11628)\"\" \"About 
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let x =number of cm each side of the rectangle was increased
\n" ); document.write( "area of rectangle = length * width
\n" ); document.write( "length of new rectangle = (x+6)cm
\n" ); document.write( "width of new rectangle = (x+4)cm
\n" ); document.write( "given area of new triangle =39 cm^2\r
\n" ); document.write( "\n" ); document.write( "(x+6)(x+4)=39
\n" ); document.write( "x^2+10x+24=39
\n" ); document.write( "x^2+10x-15=0
\n" ); document.write( "use the following quadratic formula to solve for x
\n" ); document.write( "with a =1,b=10,c=-15\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"\r
\n" ); document.write( "\n" ); document.write( "x=((-10)ħsqrt(10^2-4*1*(-15))/2*1
\n" ); document.write( " = ((-10)ħsqrt(100+60)=-10ħsqrt(160))2
\n" ); document.write( "
\n" ); document.write( "=(-10ħ12.65)/2=2.65/2 or -22.65/2
\n" ); document.write( "=1.33 or -11.33(reject)\r
\n" ); document.write( "\n" ); document.write( "ans: each side of the rectangle was increased by 1.33 cm\r
\n" ); document.write( "\n" ); document.write( "check: 7.33*5.33=39.07 (approximate because of rounding to two decimal places)
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