document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=391297>Question 391297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would I find the linear factor of 2x^2 - x - 6?\r<BR>\n" );
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document.write( "My email is angelsgirl24@embarqmail.com\r<BR>\n" );
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document.write( "Thank you for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #277583 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=277583\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Jennifer_Sadler@stu.southuniversity.edu\r<BR>\n" );
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document.write( "2x^(2)-x-6\r<BR>\n" );
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document.write( "In this problem (3)/(2)*-2=-6 and (3)/(2)-2=-1, so insert (3)/(2) as the right hand term of one factor and -2 as the right-hand term of the other factor.<BR>\n" );
document.write( "(x+(3)/(2))(x-2)\r<BR>\n" );
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document.write( "Remove the fraction by multiplying the first term of the factor by the denominator of the second term.<BR>\n" );
document.write( "(2x+3)(x-2) </SPAN>\n" );
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