document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=391156>Question 391156</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in equilateral triangle one angle measures 3x+y the other 2x+40 and the third 2y what is the value of x and what is the value of y  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #277506 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=277506\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+y = 60<BR>\n" );
document.write( "2x+  40 = 60<BR>\n" );
document.write( "2y = 60, because equilateral <==> equiangular.\r<BR>\n" );
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document.write( "Then y = 30 degrees, and x = 10 degrees. </SPAN>\n" );
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