document.write( "Question 391191: how much of an 85% solution of antifreeze should be added to 5L of a 45% solution to produce a 60% solution \n" ); document.write( "

Algebra.Com's Answer #277485 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"a\"$ = L of 85% solution to be added
\n" ); document.write( " $\".85a\"$ = L of additive
\n" ); document.write( "given:
\n" ); document.write( " $\".45%2A5+=+2.25\"$ L of additive in 45% solution
\n" ); document.write( "-----------------
\n" ); document.write( "In words:
\n" ); document.write( "(L of additive)/(L of solution) = 60%
\n" ); document.write( " $\"%28.85a+%2B+2.25%29%2F%28a+%2B+5%29+=+.6\"$
\n" ); document.write( " $\".85a+%2B+2.25+=+.6%2A%28a+%2B+5%29\"$
\n" ); document.write( " $\".85a+%2B+2.25+=+.6a+%2B+3\"$
\n" ); document.write( " $\".25a+=+.75\"$
\n" ); document.write( " $\"a+=+3\"$
\n" ); document.write( "3 Liters of 85% solution should be added
\n" ); document.write( "check:
\n" ); document.write( " $\"%28.85a+%2B+2.25%29%2F%28a+%2B+5%29+=+.6\"$
\n" ); document.write( " $\"%28.85%2A3+%2B+2.25%29%2F%283+%2B+5%29+=+.6\"$
\n" ); document.write( " $\"%282.55+%2B+2.25%29%2F8+=+.6\"$
\n" ); document.write( " $\"4.8%2F8+=+.6\"$
\n" ); document.write( " $\"4.8+=+4.8\"$
\n" ); document.write( "OK \n" ); document.write( "

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