document.write( "Question 390894: an architect is allowed no more then 15 square meters to add a small bedroom to a house. Because of the rooms design in relationship to the existing structure, the width of it's rectangle floor must be 7 meters less than two times the length. Find the precise length and width of the rectangular floor of maximum area that the architect is permitted.
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Algebra.Com's Answer #277472 by ankor@dixie-net.com(22740)\"\" \"About 
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an architect is allowed no more then 15 square meters to add a small bedroom to a house.
\n" ); document.write( "Because of the rooms design in relationship to the existing structure, the width
\n" ); document.write( " of it's rectangle floor must be 7 meters less than two times the length.
\n" ); document.write( " Find the precise length and width of the rectangular floor of maximum area that the architect is permitted.
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\n" ); document.write( "Let x = the required length
\n" ); document.write( "then
\n" ); document.write( "(2x-7) = the required width
\n" ); document.write( ":
\n" ); document.write( "The area:
\n" ); document.write( "x(2x-7) = 15
\n" ); document.write( "2x^2 - 7x - 15 = 0
\n" ); document.write( "You can solve this using the quadratic formula, but this will factor
\n" ); document.write( "(2x + 3)(x-5) = 0
\n" ); document.write( "The positive solution
\n" ); document.write( "x = 5 m is the length
\n" ); document.write( "then
\n" ); document.write( "2(5)-7 = 3 m is the width
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