document.write( "Question 390882: find two positive numbers so that twice their sum equals their product and one number is 9 times the other number \n" ); document.write( "

Algebra.Com's Answer #277455 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
: find two positive numbers so that twice their sum equals their product and one number is 9 times the other number
\n" ); document.write( ":
\n" ); document.write( "Let x = one number
\n" ); document.write( "then
\n" ); document.write( "9x = the other number
\n" ); document.write( ":
\n" ); document.write( "2(9x + x) = x * 9x
\n" ); document.write( "2(10x) = 9x^2
\n" ); document.write( "20x = 9x^2
\n" ); document.write( "divide both sides by x
\n" ); document.write( "20 = 9x
\n" ); document.write( "x = $\"20%2F9\"$ is one number
\n" ); document.write( "9* $\"20%2F9\"$ = 20 is the other number
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See if this is true in the original statement:
\n" ); document.write( "\"two positive numbers that twice their sum equals their product\"
\n" ); document.write( "2( $\"20%2F9\"$ + 20) = $\"20%2F9\"$ * 20
\n" ); document.write( "2( $\"20%2F9\"$ + $\"180%2F9\"$ ) = $\"400%2F9\"$
\n" ); document.write( "2( $\"200%2F9\"$ ) = $\"400%2F9\"$
\n" ); document.write( " \n" ); document.write( "

\n" );