document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=391153>Question 391153</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in equilateral triangle one angle measures 3x+y the other 2x+40 and the third 2y. what is x and what is y  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #277445 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=277445\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Each angle must measure 60 degrees. Therefore, 2y = 60 --> y = 30.\r<BR>\n" );
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document.write( "Now use the first angle 3x + y, replace y with 30. It is equal to 60, so x is 10.\r<BR>\n" );
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document.write( "The remaining angle, 2x+40, is already equal to 60 since if we replace x with 10, we get 60.\r<BR>\n" );
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document.write( "So, x = 10, y = 30. </SPAN>\n" );
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