document.write( "Question 390901: There are two lamp posts (A and B) both 9.6m tall.
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document.write( "When a man 1.6m tall stand X meters in front of lamp post A, his shadow casted by lampost B just touches the base of lampost A.
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document.write( "The man then walks towards lamp post B for 12m and his shadow, casted by lamp post A, just touches the base of Lamp post B.
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document.write( "What is the length of the man's shadow (show all working out)? \n" );
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Algebra.Com's Answer #277429 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! There are two lamp posts (A and B) both 9.6m tall. \n" ); document.write( "When a man 1.6m tall stand X meters in front of lamp post A, his shadow casted \n" ); document.write( " by lampost B just touches the base of lampost A. \n" ); document.write( "The man then walks towards lamp post B for 12m and his shadow, casted by lamp \n" ); document.write( " post A, just touches the base of Lamp post B. \n" ); document.write( "What is the length of the man's shadow. \n" ); document.write( ": \n" ); document.write( "We can use the rule of similar right triangles here \n" ); document.write( "The sides of the large triangle formed by the light pole (9.6) and the dist \n" ); document.write( "between the poles, (2x+12) \n" ); document.write( ": \n" ); document.write( "The sides of the small triangle formed by the man (1.6) and the dist from \n" ); document.write( "him to the light pole, x \n" ); document.write( ": \n" ); document.write( "A ratio equation \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "9.6x = 1.6(2x+12) \n" ); document.write( "9.6x = 3.2x + 19.2 \n" ); document.write( "9.6x - 3.2x = 19.2 \n" ); document.write( "6.4x = 19.2 \n" ); document.write( "x = \n" ); document.write( "x = 3 meters is the guys shadow \n" ); document.write( " |