document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=391072>Question 391072</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2.	Solve the system by addition.<BR>\n" );
document.write( "	x + y = 8<BR>\n" );
document.write( "	x – y = 8\r<BR>\n" );
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document.write( "3.	Solve the system by addition.<BR>\n" );
document.write( "	5x – 3y = 13<BR>\n" );
document.write( "	4x – 3y = 11<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #277419 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=277419\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm pretty sure you can easily solve both systems by adding the two equations together (besides, the problem tells you how to solve it). However, you'll have to multiply one of the equations on the second problem by -1, so that you can add and the y's will cancel out. </SPAN>\n" );
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