document.write( "Question 391110: How many different ways of order can four objects be lined up? \n" ); document.write( "

Algebra.Com's Answer #277401 by solver91311(24713) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Presuming they are 4 distinctly different objects, then there are 4 ways to pick the first object. For each of those 4 ways to pick the first object there are 3 ways to pick the second object, making a total of 12 ways to pick the first two objects, and so on times 2 then times 1.\r
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\n" ); document.write( "\n" ); document.write( "Shorthand is 4! = 4 X 3 X 2 X 1\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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