document.write( "Question 5287: The sum of two numbers is 23. Twice the greater number added to three times the smaller number is 57. \n" ); document.write( "

Algebra.Com's Answer #2774 by guapa(62) $\"\"$ $\"About$

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Let x be the smaller number then y is the greater.
\n" ); document.write( "The sum (+) of two numbers (x, y) is (=) 23. Thus, x+y=23 This is our first equation.
\n" ); document.write( "You can solve this equation for x or y. Let's do it for x. x=23-y
\n" ); document.write( "Now, twice the greater number (2y) added (+) to three times the smaller number (3x)is 57 (=57)
\n" ); document.write( "So, the second equation is: 2y + 3x = 57
\n" ); document.write( "Now substitute (23-y) for x:
\n" ); document.write( "2y + 3(23-y)=57
\n" ); document.write( "2y+ 69-3y= 57
\n" ); document.write( "69-y=57
\n" ); document.write( "y=12
\n" ); document.write( "If y =12 then x=23-y equals x=23-12, x= 11
\n" ); document.write( "Now we can check our answers: x+y = 23, 11+12=23
\n" ); document.write( "And 2y+3x = 57, 2(12)+3(11)=57, 24+33=57 \n" ); document.write( "

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