document.write( "Question 391077: the sum of three numbers is 137. the second number is 4 more than two times the first number. The third number is 5 less than three times the first number. Find the three numbers. \n" ); document.write( "
Algebra.Com's Answer #277387 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! x+2x+4+3x-5=137 \n" ); document.write( "6x=138 \n" ); document.write( "x=23 \n" ); document.write( "2x+4=50 \n" ); document.write( "3x-5=64 \n" ); document.write( " |