document.write( "Question 42645: Find two consecutive integers such that the sum of 2 times the first integer and 4 times second integer is 46. \n" ); document.write( "

Algebra.Com's Answer #27737 by Socom491(19) $\"\"$ $\"About$

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Let n= First Integer
\n" ); document.write( "Let n+1= Second Integer\r
\n" ); document.write( "\n" ); document.write( " $\"2n%2B4%28n%2B1%29=46\"$
\n" ); document.write( " $\"2n%2B4n%2B4=46\"$
\n" ); document.write( " $\"6n%2B4=46\"$
\n" ); document.write( " $\"++-4=-4\"$
\n" ); document.write( " $\"6n=42\"$
\n" ); document.write( " $\"6n%2F6=42%2F6\"$
\n" ); document.write( " n=7\r
\n" ); document.write( "\n" ); document.write( "Now we plug 7 into the n statements,
\n" ); document.write( "so the first number is 7 and the second is 8. \n" ); document.write( "

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