document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42659>Question 42659</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me with this equation\r<BR>\n" );
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document.write( "3t+1/2t=28    solve and check\r<BR>\n" );
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document.write( "can you explain how you get the answer\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27735 by </B><A HREF=/tutors/aboutme.mpl?userid=Socom491><B>Socom491(19)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Socom491><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27735\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ok, so first we have to combine the like terms, which are 3t and 1/2t, when we do this we get 3 and 1/2t, so now we plug it in to the equation.\r<BR>\n" );
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document.write( "3 1/2t=28<BR>\n" );
document.write( "/3 1/2= / 3 1/2\r<BR>\n" );
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document.write( "And...28 divided by 3.5 equals 8. So t=8.\r<BR>\n" );
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document.write( "To check we plug eight in replacement of t's.<BR>\n" );
document.write( "3(8)+1/2(8)=28...and it checks.<BR>\n" );
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