document.write( "Question 42654: Find two consecutive integers such that the sum of 2 times the first integer and 4 times second integer is 46 \n" ); document.write( "

Algebra.Com's Answer #27734 by psbhowmick(878) $\"\"$ $\"About$

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Find two consecutive integers such that the sum of 2 times the first integer and 4 times second integer is 46\r
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\n" ); document.write( "\n" ); document.write( "Let the consecutive integers be 'n' and 'n+1'.
\n" ); document.write( "Two times first integer = 2n.
\n" ); document.write( "Four times second integer = 4(n+1).
\n" ); document.write( "Then their sum = 2n + 4(n+1) = 6n+4.
\n" ); document.write( "Given: this sum = 46.
\n" ); document.write( "So 6n+4 = 46
\n" ); document.write( "or 6n = 46 - 4 = 42
\n" ); document.write( "or n = 42/6 = 7\r
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\n" ); document.write( "\n" ); document.write( "Hence the consecutive numbers are n = 7 and (n+1) = 7+1 = 8. \n" ); document.write( "

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