document.write( "Question 42655: \"Image \n" ); document.write( "
Algebra.Com's Answer #27733 by psbhowmick(878)\"\" \"About 
You can put this solution on YOUR website!
Perimeter = 2(Length + Width)
\n" ); document.write( "or P = 2((2x - 5) + x) = 2(3x - 5)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Given: P = 50 in.
\n" ); document.write( "So 50 = 2(3x - 5)
\n" ); document.write( "or \"50%2F2+=+%283x+-+5%29\"
\n" ); document.write( "or 25 = 3x - 5
\n" ); document.write( "or 3x = 25 + 5 = 30
\n" ); document.write( "or \"x+=+30%2F3\"
\n" ); document.write( "or x = 10 in\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hence, Length = (2x - 5) = 2 x 10 - 5 = 20 - 5 = 15 in
\n" ); document.write( "and width = x = 10 in.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Thus the length and width are 15 in and 10 in respectively.
\n" ); document.write( "
\n" );