document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389458>Question 389458</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A box has the dimensions of 2 inches by 3 inches by 4 inches. Determine the approximate angle formed by the diagonal of the 2 X 3 side and the diagonal of the 3 X 4 side to the nearest degree? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #277251 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=277251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the length of the base be 4 inches, the width of the base be 3 inches, and the height, 2 inches.  Then the measure of the diagonal of the 2x 3 face is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2813%29 ALIGN=MIDDLE  ALT=\"sqrt%2813%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, the measure of the diagonal of the 3x 4 face is 5, and the  measure of the diagonal of the 2x 4 face is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2sqrt%285%29 ALIGN=MIDDLE  ALT=\"2sqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  The three diagonals form a triangle.  Then from the cosine law, \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=20+=+25+%2B+13+-+2%2A5%2Asqrt%2813%29%2Acos%28theta%29 ALIGN=MIDDLE  ALT=\"20+=+25+%2B+13+-+2%2A5%2Asqrt%2813%29%2Acos%28theta%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "===><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+-18+=+-10sqrt%2813%29cos%28theta%29 ALIGN=MIDDLE  ALT=\"+-18+=+-10sqrt%2813%29cos%28theta%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "===><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cos%28theta%29+=+%289sqrt%2813%29%29%2F65 ALIGN=MIDDLE  ALT=\"cos%28theta%29+=+%289sqrt%2813%29%29%2F65\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "===> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=theta+=+60 ALIGN=MIDDLE  ALT=\"theta+=+60\"   DISABLED_style= \"max-width:90%; height:auto;\" >degrees, to the nearest degree. </SPAN>\n" );
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