document.write( "Question 390783: Make up a rational function graph that meets the following conditions:
\n" ); document.write( "a)it will have an oblique asymptote of slope \"not equal\" to 1.
\n" ); document.write( "b)it will have two x-intercepts, one of multiplicity 1 and the other 2.
\n" ); document.write( "c)it will have two vertical asymptotes.
\n" ); document.write( "Then, go through the complete process of graphing your rational function, showing all steps, including the long division. \n" ); document.write( "

Algebra.Com's Answer #277196 by robertb(5830) $\"\"$ $\"About$

You can put this solution on YOUR website!
Whoa, STUDENT, you ask too much, he he. But I'll show you one rational function that will satisfy your conditions. Maybe some other tutor will show you the graphing/long dividing parts. \r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29+=+%28%283x+-6%29%28x%2B1%29%5E2%29%2F%28%282x-1%29%28x%2B3%29%29\"$ .\r
\n" ); document.write( "\n" ); document.write( "The degree of the top polynomial is 3, the bottom, 2, so after long division, the quotient is a linear function whose slope is 3/2. (You can even determine this by inspection!)
\n" ); document.write( "The roots of the function (which correspond to the x-intercepts) are 2 (multiplicity 1), and -1 (multiplicity 2).
\n" ); document.write( "The roots OF THE BOTTOM EXPRESSION, 1/2 and -3, yield the vertical asymptotes. The equations are exactly x = 1/2 and x = -3. \n" ); document.write( "

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