document.write( "Question 390729: The line passing through (x,4) and (4,-5) is perpendicular to a line with a slope of -7/3. What is the value of x? \n" ); document.write( "
Algebra.Com's Answer #277171 by ankor@dixie-net.com(22740)\"\" \"About 
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The line passing through (x,4) and (4,-5) is perpendicular to a line with a slope of -7/3.
\n" ); document.write( " What is the value of x?
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\n" ); document.write( "Find the slope of the line perpendicular to slope of -7/3 using: m1*m2 = -1
\n" ); document.write( "Let m1 = -7/3, find m2
\n" ); document.write( "\"-7%2F3\"*m2 = -1
\n" ); document.write( "m2 = \"-3%2F7\"*-1
\n" ); document.write( "m2 = \"3%2F7\"
\n" ); document.write( ":
\n" ); document.write( "Use the slope formula \"%28y2-y1%29%2F%28x2-x1%29\" = m2
\n" ); document.write( "Using the given values
\n" ); document.write( "\"%28-5-4%29%2F%284-x%29\" = \"3%2F7\"
\n" ); document.write( ":
\n" ); document.write( "\"%28-9%29%2F%284-x%29\" = \"3%2F7\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "3(4-x) = -9*7
\n" ); document.write( "12 - 3x = -63
\n" ); document.write( "-3x = -63 - 12
\n" ); document.write( "-3x = -75
\n" ); document.write( "x = \"%28-75%29%2F%28-3%29\"
\n" ); document.write( "x = +25
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the slope using x=25
\n" ); document.write( "\"%28-5-4%29%2F%284-25%29\" =
\n" ); document.write( "\"%28-9%29%2F%28-21%29\" = \"3%2F7\"
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