document.write( "Question 390713: for the following equation, state the value of the discriminant and then describe the nature of the solutions 18x^2+10x+14=0 \n" ); document.write( "
Algebra.Com's Answer #277083 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
From \"18x%5E2%2B10x%2B14\" we can see that \"a=18\", \"b=10\", and \"c=14\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"D=b%5E2-4ac\" Start with the discriminant formula.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"D=%2810%29%5E2-4%2818%29%2814%29\" Plug in \"a=18\", \"b=10\", and \"c=14\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"D=100-4%2818%29%2814%29\" Square \"10\" to get \"100\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"D=100-1008\" Multiply \"4%2818%29%2814%29\" to get \"%2872%29%2814%29=1008\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"D=-908\" Subtract \"1008\" from \"100\" to get \"-908\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the discriminant is \"D=-908\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since the discriminant is less than zero, this means that there are two complex solutions.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In other words, there are no real solutions.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Jim
\n" ); document.write( "
\n" );