document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=390686>Question 390686</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sailboat travels 12 miles downstream in only 2 hours. The return trip upstream takes 3 hours. Find the rate of speed of the current. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #277057 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=277057\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "R=D/T<BR>\n" );
document.write( "R=12/2=6 MPH DOWNSTREAM.<BR>\n" );
document.write( "R=12/3=4 MPH UPSTREAM.<BR>\n" );
document.write( "The rate here = the speed of the sailboat + or - the current.<BR>\n" );
document.write( "6=R+C<BR>\n" );
document.write( "4=R-C<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "10=2R<BR>\n" );
document.write( "2R=10<BR>\n" );
document.write( "R=10/2<BR>\n" );
document.write( "R=5 MPH FOR THE SAILBOAT<BR>\n" );
document.write( "THUS THE CURRENT IS:<BR>\n" );
document.write( "6=5+C<BR>\n" );
document.write( "C=6-5=1 MPH.<BR>\n" );
document.write( "4=5-C<BR>\n" );
document.write( "-C=4-5<BR>\n" );
document.write( "-C=-1<BR>\n" );
document.write( "C=1 MPH.<BR>\n" );
document.write( " <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );