document.write( "Question 390634: The length of a rectangle is 7 feet more than its width. The length of a diagonal of the rectangle is 9 feet more than the width. By algebraic methods find the width of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #277025 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,         
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document.write( "Let w ,(w+7ft),(w+9ft)represent the width,length and diagonal respectively
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document.write( "Using the Pytahgorean Theorem
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document.write( " w^2  + (w+7)^2 = (w+9)^2
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document.write( " w^2 + w^2 + 14w + 49 = w^2 + 18w + 81
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document.write( "   w^2 -4w - 32 = 0
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document.write( "factoring
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document.write( " (w-8)(w+4) = 0
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document.write( "  (w+4) = 0
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document.write( "    w = -4  Tossing out negative solution for length
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document.write( "  (w-8) = 0
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document.write( "      w = 8ft,  the width of the rectangle   (length=15ft, diagonal=17ft)\r
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document.write( "CHECKING our Answer
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document.write( "   64 + 225 = 289 \n" );
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