document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=743>Question 743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars leave town at the same time going in opposite directions. one travels at 35 km/h and the other at 55 km/h. in how many hours will they be 200 km apart? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #277 by </B><A HREF=/tutors/aboutme.mpl?userid=pushpaharan><B>pushpaharan(47)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pushpaharan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=277\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the time taken for 200 km apeart.<BR>\n" );
document.write( "in x hrs car \"A\" will go x*35 km (distance =speed * time)<BR>\n" );
document.write( "in x hrs car \"B\" will go x*55 km\r<BR>\n" );
document.write( "\n" );
document.write( "togather both will go 35x+55x = 200<BR>\n" );
document.write( "90x = 200<BR>\n" );
document.write( "x=200/90 hts<BR>\n" );
document.write( "x= 2 hrs and 2/9 hrs<BR>\n" );
document.write( " = 2 hrs and 2/9*60 mins<BR>\n" );
document.write( " = 2 hrs and 13 mins </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );