document.write( "Question 390548: I dont get how to solve equations by graphing.
\n" ); document.write( "Could you please show step by step how to do this?\r
\n" ); document.write( "\n" ); document.write( "-x^3 -3x-2=0\r
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\n" ); document.write( "\n" ); document.write( "x^4+2x^2-1=0\r
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\n" ); document.write( "\n" ); document.write( "y=-x^4+4x^3+3=0\r
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\n" ); document.write( "\n" ); document.write( "-x^3+3x+4=0\r
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\n" ); document.write( "\n" ); document.write( "x^4+2x-3=0\r
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\n" ); document.write( "\n" ); document.write( "-x^3 +2x^2 +1=0\r
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\n" ); document.write( "\n" ); document.write( "Any help you can give wuld be greatly appreciated
\n" ); document.write( "Thank you
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Algebra.Com's Answer #276965 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
I dont get how to solve equations by graphing.
\n" ); document.write( "Could you please show step by step how to do this?
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\n" ); document.write( "You would have to plot enough points to see where
\n" ); document.write( "the curve crosses the x-axis.
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\n" ); document.write( "-x^3 -3x-2=0
\n" ); document.write( "If x = 0, y = -2 giving (0,-2)
\n" ); document.write( "If x = -1, y = 1+3-2 = 2 giving (-1,2)
\n" ); document.write( "Note: Since the y-value changed from negative
\n" ); document.write( "to positive, there must be a root between
\n" ); document.write( "x = -1 and x = 0
\n" ); document.write( "Try x = -1/2:
\n" ); document.write( "If x = -1/2, y = -(-1/8)-(-1/2)-2 = (1/8)+(4/8)-2 = -1 3/8
\n" ); document.write( "giving you (-1/2,-11/8)
\n" ); document.write( "Keeping up this process you can get closer and closer to the solution
\n" ); document.write( "which is -0.596072...
\n" ); document.write( "\"graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C-x%5E3-3x-2%29\"
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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