document.write( "Question 390451: The length of a rectangle is 5 times 2 less than the width. The perimeter of the rectangle 100 feet. What is the width? \n" ); document.write( "
Algebra.Com's Answer #276927 by mananth(16946)![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 5 times 2 less than the width. The perimeter of the rectangle 100 feet. What is the width? \n" ); document.write( "... \n" ); document.write( "Let width be w \n" ); document.write( "Length = 5(w-2) \n" ); document.write( "2(L+W)= perimeter \n" ); document.write( "2*(w+5(w-2))=100 \n" ); document.write( "2*(w+5w-10)=100 \n" ); document.write( "/2 \n" ); document.write( "6w-10=50 \n" ); document.write( "6w=60 \n" ); document.write( "w=10 \n" ); document.write( "w=10feet \n" ); document.write( "Length = 5*(10-2) \n" ); document.write( "Length = 5*8 \n" ); document.write( "Length = 40 feet \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |