document.write( "Question 390451: The length of a rectangle is 5 times 2 less than the width. The perimeter of the rectangle 100 feet. What is the width? \n" ); document.write( "
Algebra.Com's Answer #276927 by mananth(16946)\"\" \"About 
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The length of a rectangle is 5 times 2 less than the width. The perimeter of the rectangle 100 feet. What is the width?
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\n" ); document.write( "Let width be w
\n" ); document.write( "Length = 5(w-2)
\n" ); document.write( "2(L+W)= perimeter
\n" ); document.write( "2*(w+5(w-2))=100
\n" ); document.write( "2*(w+5w-10)=100
\n" ); document.write( "/2
\n" ); document.write( "6w-10=50
\n" ); document.write( "6w=60
\n" ); document.write( "w=10
\n" ); document.write( "w=10feet
\n" ); document.write( "Length = 5*(10-2)
\n" ); document.write( "Length = 5*8
\n" ); document.write( "Length = 40 feet
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\n" ); document.write( "m.ananth@hotmail.ca
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