document.write( "Question 390273: Write the slope-intercept equation of the line perpendicular to y = 5/2 x - 2, which passes though the point (0, 2). \n" ); document.write( "
Algebra.Com's Answer #276915 by emargo19(101)\"\" \"About 
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Let m1 be slope for line y = 5/2 x - 2
\n" ); document.write( "Let m2 be slope for the line perpendicular to it.
\n" ); document.write( "Therefore m1=5/2 for line y=5/2x-2
\n" ); document.write( "We have to find m2.
\n" ); document.write( "To find the slope of a perpendicular line we use the equation
\n" ); document.write( "m1.m2= -1
\n" ); document.write( "5/2.m2= -1
\n" ); document.write( "m2= -2/5
\n" ); document.write( "Use the point slope form of the line to generate the equation for the perpendicular line.
\n" ); document.write( "The lines passes through the points (0,2)
\n" ); document.write( "y-y1 = m(x-x1)
\n" ); document.write( "y-2 = -2/5(x-0)
\n" ); document.write( "y-2 = -2/5x+0
\n" ); document.write( "y = -2/5x+2
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