document.write( "Question 390508: the sum of the digit of a two digit number is 11. when the digits are reversed, the new number is 24 less than four time the original number. what is the original number?
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Algebra.Com's Answer #276898 by mananth(16946)\"\" \"About 
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the sum of the digit of a two digit number is 11. when the digits are reversed, the new number is 24 less than four time the original number. what is the original number?
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\n" ); document.write( "let the ten's digit be x
\n" ); document.write( "units digit be y
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\n" ); document.write( "x+y =11........................1
\n" ); document.write( "10y+x=4(10x+y)-24
\n" ); document.write( "10y+x=40x+4y-24
\n" ); document.write( "6y-39x=-24.....................2
\n" ); document.write( "multiply (1) by -6
\n" ); document.write( "-6x-6y=-66
\n" ); document.write( "add it to(2)
\n" ); document.write( "-6x-39x-6y+6y=--66-24
\n" ); document.write( "-45x=-90
\n" ); document.write( "/-45
\n" ); document.write( "x=2
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\n" ); document.write( "x+y=11
\n" ); document.write( "plug x
\n" ); document.write( "2+y=11
\n" ); document.write( "y=9
\n" ); document.write( "So the number is 29
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\n" ); document.write( "m.ananth@hotmail.ca
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