document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=390472>Question 390472</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the second root of the quadratic equation x^2 + 9x + k = 0 if one root is -2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #276855 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=276855\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the second root of the quadratic equation <BR>\n" );
document.write( "x^2 + 9x + k = 0 if one root is -2.<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Using synthetic division you get:<BR>\n" );
document.write( "-2)....1....9....k<BR>\n" );
document.write( ".........1....7...|k-14<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Solve k-14 = 0<BR>\n" );
document.write( "k = 14<BR>\n" );
document.write( "==========================<BR>\n" );
document.write( "Notice the quotient is x+7<BR>\n" );
document.write( "So the 2nd root is x=-7<BR>\n" );
document.write( "================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );