document.write( "Question 390467: is this correct?
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document.write( "x-0.03x=0.97
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document.write( "x(1+0.03x)=0.97
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document.write( " 1.03x=0.97
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document.write( " x=0.97/1.03
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document.write( " x=0.941\r
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Algebra.Com's Answer #276852 by richard1234(7193) You can put this solution on YOUR website! Your first step to your second step is incorrect. It should be factored as\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x(1 - 0.03)= 0.97 (there is also no x after 0.03)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0.97x = 0.97\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 1 \n" ); document.write( " |