document.write( "Question 390439: Two years ago Sam's age was 2/3 of Pam's. Three years from now Sam's age will be 3/4 of Pam's age. In 20 yrs, their combined ages will be 69. How old is Sam now? \n" ); document.write( "
Algebra.Com's Answer #276818 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Two years ago Sam's age was 2/3 of Pam's. Three years from now Sam's age will be 3/4 of Pam's age. In 20 yrs, their combined ages will be 69. How old is Sam now?\r \n" ); document.write( "\n" ); document.write( "2 years ago\r \n" ); document.write( "\n" ); document.write( "let Pam's age be x, \n" ); document.write( "Sam age = 2x/3 \r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "After 20 years \n" ); document.write( "pams age = x+22 \n" ); document.write( "Sam's age = 2x/3 +22 \n" ); document.write( ".. \n" ); document.write( "x+22+2x/3 +22=69 \n" ); document.write( "x+2x/3 +44=69 \n" ); document.write( "(3x+2x)/3 = 69-44 \n" ); document.write( "5x/3 = 25 \n" ); document.write( "5x= 25*3 \n" ); document.write( "5x=75 \n" ); document.write( "/5 \n" ); document.write( "x=15 Pam's age 2 years ago. \n" ); document.write( "Sam's age 2 years ago =2x/3 = 2*15/3=10 years. \n" ); document.write( ".. \n" ); document.write( "Sam's age now = 10+2 = 12 years \n" ); document.write( ".. \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |