document.write( "Question 42581: Find the equation of the line through the given point that is perpendicular to the given line y=3x+5, Q(1,2) \n" ); document.write( "
Algebra.Com's Answer #27678 by jmg(22)\"\" \"About 
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In the equation y = 3x + 5 , the number in front of x is the slope. \r
\n" ); document.write( "\n" ); document.write( "That means the slope is 3. The slope of a line perpendicular to that line would be the negative reciprocal which would be -1/3\r
\n" ); document.write( "\n" ); document.write( "Fill the slope along with the point Q into the point-slope form:
\n" ); document.write( "y - y sub 1 = m ( x - x sub 1) m stands for slope \r
\n" ); document.write( "\n" ); document.write( "y - 2 = (-1/3)(x - 1) distribute the -1/3
\n" ); document.write( "y - 2 = (-1/3)x + 1/3 bring the -2 across
\n" ); document.write( "y = (-1/3)x + 2 and 1/3
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