document.write( "Question 390276: Solve.\r
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Algebra.Com's Answer #276774 by richard1234(7193)\"\" \"About 
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Letting \"z+=+w%5E2\", substitute:\r
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\n" ); document.write( "\n" ); document.write( "\"z%5E2+-+18z+-+2+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "By the quadratic formula, \"z+=+%2818+%2B-+sqrt%28332%29%29%2F2+=+9+%2B-+sqrt%2883%29\" If \"z+=+9+%2B+sqrt%2883%29\" then \"w+=+0+%2B-+sqrt%289+%2B+sqrt%2883%29%29\". Likewise, if \"z+=+9+-+sqrt%2883%29\" then \"w+=+0+%2B-+sqrt%289+-+sqrt%2883%29%29\" (this gives two real and two complex values for w).
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