document.write( "Question 390284: The speed of an aircraft traveling against the wind was 445mph. When the aircraft was traveling with the wind, the speed was 515mph. Find the speed of the aircraft in still air? \n" ); document.write( "
Algebra.Com's Answer #276770 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
\n" ); document.write( "Let r=rate (speed) of plane in still air
\n" ); document.write( "And let w=speed of the wind\r
\n" ); document.write( "\n" ); document.write( "r-w=445 against wind, subtract wind speed.-----eq1
\n" ); document.write( "r+w=515 with wind, add wind speed----eq2\r
\n" ); document.write( "\n" ); document.write( "add eq1 and eq2 and we get:
\n" ); document.write( "2r=960
\n" ); document.write( "r=480----speed of plane in still air\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps--ptaylor
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